Question

已知13x²+mχ²＋11χ＋n能被13x²﹣6χ＋5整除,求m,n

第一个是13χ³

Answer 1

x +(m+6)/13
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13x²﹣6χ＋5 | 13x3+mχ²＋11χ ＋n
13x^3-6x^2 +5x
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(m+6)x^2+6x + n
(m+6)x^2-6(m+6)/13x+5(m+6)/13
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0
所以 6+6(m+6)/13=0 , n-5(m+6)/13=0
m=-19,n=-5

Answer 2

13χ³+mχ²＋11χ＋n
=(13χ³-6χ²+5x)+(m+6)χ²+6x+n
=x(13χ²-6x+5)-[-(m+6)χ²-6x+5]+(n+5)
所以：-(m+6)=13, n+5=0
m=-19
n=-5