已知函数f(x)=2sin(1/3x-π/6)
(1)求f(5π/4)(2)设α,β∈[0,π/2],f(3α+π/2)=10/13,f(3β+π/2)=6/5.求cos(α+β)的值....
(1)求f(5π/4)
(2)设α,β∈[0,π/2],f(3α+π/2)=10/13,f(3β+π/2)=6/5.求cos(α+β)的值. 展开
(2)设α,β∈[0,π/2],f(3α+π/2)=10/13,f(3β+π/2)=6/5.求cos(α+β)的值. 展开
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(1)π=180°
所以f(5π/4) =2sin(5/4*1/3π-π/6)=2sin45°=根号2
(2)f(3α+π/2)=2sin(α+π/6-π/6)=2sinα=10/13 sinα=5/13
f(3β+π/2)=2sinβ=6/5 sinβ=3/5
因为sin^2(α)+cos^2(α)=1且α,β∈[0,π/2],
所以cosα=12/13 cosβ=4/5
cos(α+β)=cosαcosβ-sinαsinβ=33/65
所以f(5π/4) =2sin(5/4*1/3π-π/6)=2sin45°=根号2
(2)f(3α+π/2)=2sin(α+π/6-π/6)=2sinα=10/13 sinα=5/13
f(3β+π/2)=2sinβ=6/5 sinβ=3/5
因为sin^2(α)+cos^2(α)=1且α,β∈[0,π/2],
所以cosα=12/13 cosβ=4/5
cos(α+β)=cosαcosβ-sinαsinβ=33/65
追问
第二小题错了,f(3β+π)=6/5.求cos(α+β)的值.
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