
分解因式(x-y)³+4(y-x),(x+y)²+4(y+x+1),x²-4y²+12yz-9z²
3个回答
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(x-y)³+4(y-x)
=(x-y)[(x-y)²-4]
=(x-y)(x-y+2)(x-y-2)
(x+y)²+4(y+x+1)
=(x+y)²+4(x+y)+4
=(x+y+2)²
x²-4y²+12yz-9z²
=x²-(4y²-12yz+9z²)
=x²-(2y-3z)²
=(x+2y-3z)(x-2y+3z)
=(x-y)[(x-y)²-4]
=(x-y)(x-y+2)(x-y-2)
(x+y)²+4(y+x+1)
=(x+y)²+4(x+y)+4
=(x+y+2)²
x²-4y²+12yz-9z²
=x²-(4y²-12yz+9z²)
=x²-(2y-3z)²
=(x+2y-3z)(x-2y+3z)
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1
=(x-y)[(x-y)^2-4]=(x-y)(x-y+2)(x-y-2)
2
=(x+y+2)^2
3
=x^2-(4y^2-12yz+9z^2)
=x^2-(2y+3z)^2
=(x+2y+3z)(x-2y-3z)
=(x-y)[(x-y)^2-4]=(x-y)(x-y+2)(x-y-2)
2
=(x+y+2)^2
3
=x^2-(4y^2-12yz+9z^2)
=x^2-(2y+3z)^2
=(x+2y+3z)(x-2y-3z)
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1. (x-y)(x-3)(x+1)
2.[(x+y)+2]的平方
3.[x-(2y-3z)][x+(2y-3z)]
2.[(x+y)+2]的平方
3.[x-(2y-3z)][x+(2y-3z)]
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