Question

C++程序中cin.get()的作用

#include <iostream>
#include <string>
#include <vector>

const int NUM = 5;
int main()
{
using std::vector;
using std::string;
using std::cin;
using std::cout;
using std::endl;

vector<int> ratings(NUM);
vector<string> titles(NUM);
cout << "You will do exactly as told. You will enter\n"
<< NUM << " book titles and your ratings (0-10).\n";
int i;
for (i = 0; i < NUM; i++)
{
cout << "Enter title #" << i + 1 << ": ";
getline(cin,titles[i]);
cout << "Enter your rating (0-10): ";
cin >> ratings[i];
cin.get();
}
cout << "Thank you. You entered the following:\n"
<< "Rating\tBook\n";
for (i = 0; i < NUM; i++)
{
cout << ratings[i] << "\t" << titles[i] << endl;
}

return 0;
}

在该程序第一个for循环中cin.get()；的意义在于什么？为什么输入流中会残留一个回车符？

Answer 1

cin.get()是保留回车在输入流队列中的.而cin是丢弃回车的.因为你要结束输入要以回车会标志，就看你要不要保留