Question

计算:(2^4+1/4)(4^4+1/4)(6^4+1/4)(8^4+1/4)(10^4+1/4)/(1^4+1/4)(3^4+1/4)(5^4+1/4)(7^4+1/4)(9^4+1/4)

计算:(2^4+1/4)(4^4+1/4)(6^4+1/4)(8^4+1/4)(10^4+1/4)/(1^4+1/4)(3^4+1/4)(5^4+1/4)(7^4+1/4)(9^4+1/4)
快!急！！！！！！！！！！！！！！！！！！！！！！！！
用简便方法！

Answer 1

解题过程在图片上

Answer 2

(2^4+1/4)(4^4+1/4)(6^4+1/4)(8^4+1/4)(10^4+1/4)/(1^4+1/4)(3^4+1/4)(5^4+1/4)(7^4+1/4)(9^4+1/4)
假设2,4,6,8,10,1,3,5,7,9都是x
(x^4+1/4)=(x^2)^2+x^2+(1/2)^2-x^2=(x^2+1/2)^2-x^2=(x^2+1/2-x)(x^2+1/2+x)
将x换成2,4,6,8,10,1,3,5,7,9
原式=(2^2+1/2-2)(2^2+1/2+2)(4^2+1/2-4)(4^2+1/2+4)(6^2+1/2-6)(6^2+1/2+6)(8^2+1/2-8)(8^2+1/2+8)(10^2+1/2-10)(10^2+1/2+10)/(1^2+1/2-1)(1^2+1/2+1)(3^2+1/2-3)(3^2+1/2+3)(5^2+1/2-5)(5^2+1/2+5)(7^2+1/2-7)(7^2+1/2+7)(9^2+1/2-9)(9^2+1/2+9)
=（5/2*13/2*25/2*41/2*61/2*85/2*113/2*145/2*181/2*221/2）/（1/2*5/2*13/2*25/2*41/2*61/2*85/2*113/2*145/2*181/2）
=（221/2）/（1/2）
=221 (耐心一点看完啊）

Answer 3

数学是乃来用的，不是拿来折磨人的！

Answer 4

475

Answer 5

1253688455