x³-3x²+4因式分解的过程 急
5个回答
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x³-3x²+4
=x³+x²-4(x²-1)
=x²(x+1)-4(x+1)(x-1)
=(x+1)(x²-4x+4)
=(x+1)(x-2)²
望采纳谢谢
=x³+x²-4(x²-1)
=x²(x+1)-4(x+1)(x-1)
=(x+1)(x²-4x+4)
=(x+1)(x-2)²
望采纳谢谢
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展开全部
=x³+1-3x²+3
=(x+1)(x²-x+1)-3(x+1)(x-1)
=(x-1)(x²-4x+4)
=(x+1)(x-2)²
=(x+1)(x²-x+1)-3(x+1)(x-1)
=(x-1)(x²-4x+4)
=(x+1)(x-2)²
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展开全部
x³-3x²+4
=x³+1-3x²+3
=(x+1)(x²-x+1)-3(x²-1)
=(x+1)(x²-x+1)-3(x+1)(x-1)
=(x+1)(x²-x+1-3x+3)
=(x+1)(x²-4x+4)
=(x+1)(x-2)²
=x³+1-3x²+3
=(x+1)(x²-x+1)-3(x²-1)
=(x+1)(x²-x+1)-3(x+1)(x-1)
=(x+1)(x²-x+1-3x+3)
=(x+1)(x²-4x+4)
=(x+1)(x-2)²
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x³-3x²+4
=x^3+x^2-4x^2+4
=x^2(x+1)-4(x^2-1)
=x^2(x+1)-4(x+1)(x-1)
=(x+1)(x^2-4x+4)
=(x+1)(x-2)^2
=x^3+x^2-4x^2+4
=x^2(x+1)-4(x^2-1)
=x^2(x+1)-4(x+1)(x-1)
=(x+1)(x^2-4x+4)
=(x+1)(x-2)^2
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