Question

3x(x-1)=2-2x

初三习题！用分解因式。
②2（x-3）^2=x^2-9
③(4x+2)^2=x(2x+1)

Answer 1

3x(x-1)=2-2x
3x(x-1)=-2(x-1)
3x(x-1)+2(x-1) =0
(x-1)(3x+2)=0
x1=-2/3，x2=1

②2（x-3）^2=x^2-9
2(x-3)^2=(x+3)(x-3)
2(x-3)^2-(x+3)(x-3)=0
(x-3)(2x-6-x-3)=0
(x-3)x-9)=0
x1=3，x2=9

③(4x+2)^2=x(2x+1)
4(2x+1)^2-x(2x+1)=0
(2x+1)(8x+4-x)=0
(2x+1)(7x+4)=0
x1=-4/7，x2=-1/2

Answer 2

1、3x(x-1)=2-2x
3x(x-1)+2(x-1)=0
(x-1)(3x+2)=0
x=1,x=-2/3
2、2（x-3）^2=x^2-9
2(x-3)^2-(x-3)(x+3)=0
(x-3)(2x-6-x-3)=0
(x-3)(x-9)=0
x=3,x=9

③(4x+2)^2=x(2x+1)
[2(2x+1)]^2-x(2x+1)
(2x+1)(8x+4-x)=0
x=-1/2,x=-4/7

Answer 3

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