Question

一道化学题求解

请书写下列物质在水溶液中的电离方程式:
{1}HNO3
{2}NH4NO3
{3}KOH
{4}Na2CO3
{5}CaCl2
{6}Fe(No3)2
{7}Al2（So4)3

Answer 1

{1}HNO3 = H+ + NO3-
{2}NH4NO3 = NH4+ + NO3-
{3}KOH = K+ + OH-
{4}Na2CO3 = 2 Na+ + CO32-
{5}CaCl2 = Ca2+ + 2 Cl-
{6}Fe(NO3)2 = Fe2+ + 2 NO3-
{7}Al2(SO4)3 = 2 Al3+ + 3 SO42-

Answer 2

HNO3===H+ +NO3-
NH4NO3===NH4+ +NO3-
KOH===K+ +OH-
Na2CO3===2Na+ +CO32-
CaCl2===Ca2+ +2Cl-
Fe(NO3)2===Fe2+ +2NO3-
Al2(SO4)3===2Al3+ +3SO42-