一元二次不等式详细解题过程
4+3x-x²>0x²-1≥0x²-2x﹢24≥0x²-4x+9≤0x²-2x+3>0x²-2x-3≥0﹣x&...
4+3x-x²>0
x²-1≥0
x²-2x﹢24≥0
x²-4x+9≤0
x²-2x+3>0
x²-2x-3≥0
﹣x²-3x+4<0
x²+2x≤0
(x+a)﹙x+1﹚≥0 展开
x²-1≥0
x²-2x﹢24≥0
x²-4x+9≤0
x²-2x+3>0
x²-2x-3≥0
﹣x²-3x+4<0
x²+2x≤0
(x+a)﹙x+1﹚≥0 展开
2个回答
展开全部
4+3x-x²>0
x²-3x-4<0
(x-4)(x+1)<0
-1<x<4
x²-1≥0
(x+1)(x-1)≥0
x≤-1 x≥1
x²-2x﹢24≥0
(x-1)²+23≥0
x∈R
x²-4x+9≤0
(x-2)²+5≤0
无解
x²-2x+3>0
(x-1)²+2>0
x∈R
x²-2x-3≥0
(x-3)(x+1)≥0
x≥3 x≤-1
﹣x²-3x+4<0
x²+3x-4<0
(x+4)(x-1)<0
-4<x<1
x²+2x≤0
x(x+2)≤0
-2≤x≤0
(x+a)﹙x+1﹚≥0
1)a=1
x∈R
2)a<1
x≥a x≤-1
3)a>1
x≥1 x≤a
x²-3x-4<0
(x-4)(x+1)<0
-1<x<4
x²-1≥0
(x+1)(x-1)≥0
x≤-1 x≥1
x²-2x﹢24≥0
(x-1)²+23≥0
x∈R
x²-4x+9≤0
(x-2)²+5≤0
无解
x²-2x+3>0
(x-1)²+2>0
x∈R
x²-2x-3≥0
(x-3)(x+1)≥0
x≥3 x≤-1
﹣x²-3x+4<0
x²+3x-4<0
(x+4)(x-1)<0
-4<x<1
x²+2x≤0
x(x+2)≤0
-2≤x≤0
(x+a)﹙x+1﹚≥0
1)a=1
x∈R
2)a<1
x≥a x≤-1
3)a>1
x≥1 x≤a
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