Question

数学题：解方程(2x+3)(x-4)-(x+2)(x-3)=x的平方+6 现在就要！！！！！！

Answer 1

(2x+3)(x-4)-(x+2)(x-3)=x^2+6
(2x^2-5x-12)-(x^2-x-6)=x^2+6
2x^2-5x-12-x^2+x+6=x^2+6
x^2-4x-6=x^2+6
-4x=12
x=-3

Answer 2

(2x+3)(x-4)-(x+2)(x-3)=x^2+6
(2x^2-5x-12)-(x^2-x-6)=x^2+6
2x^2-5x-12-x^2+x+6=x^2+6
x^2-4x-6=x^2+6
-4x=12
x=-3

Answer 3

(2x+3)(x-4)-(x+2)(x-3)=x²+6
2x²-8x+3x-12-(x²-3x+2x-6)=x²+6
2x²-8x=3x-12-x²+3x-2x+6=x²+6
x²-4x-6=x²+6
-4x-12=o
x=-3

Answer 4

(2x+3)(x-4)-(x+2)(x-3)=x²+6
2x²-5x-12 - (x²-x-6) - (x²+6) = 0
-4x-12=0;

=>x=-3

Answer 5

先把括号展开，化简变为：2x2-8x+3x-12-x2+3x-2x+6=x2+6
解得：x=-3