Question

解关于x的方程4题和用因式分解法解4题 急啊。。。。

关于x的方程
1. (a+b)x^2-(b+c)x-(a-c)=0 (a不等于0)
2. ax^2-c=0 (a不等于0)
3. (x^2-2x)a-(x^2-x-a)=0 (a不等于1)
4. (a-b)x^2-(a^2-b^2+1)x+(a+b)=0 (a不等于b)
用因式分解法解方程
1. (2x+1)^2=9(x-3)^2
2. 10x^2-11x-6=0
3. 9(x-2)^2=4(x+1)^2
4. (4x-1)^2+10(1-4x)-24=0
要过程

Answer 1

1. (a+b)x^2-(b+c)x-(a-c)=0 (a不等于0)
((a+b)x-(a-c))(x-1)=0
x=a-c/a+b x=1

2. ax^2-c=0 (a不等于0)
x^2=c/a
x=√ac/a或x=-√ac/a
3. (x^2-2x)a-(x^2-x-a)=0 (a不等于1)
(a-1)x^2-(2a-1)x+a=0
((a-1)x-a)(x-1)=0
x=a/a-1 x=1
4. (a-b)x^2-(a^2-b^2+1)x+(a+b)=0 (a不等于b)
((a-b)x-1)(x-(a+b))=0
x=1/a-b x=a+b
用因式分解法解方程
1. (2x+1)^2=9(x-3)^2
(2x+1)^2-9(x-3)^2=0
((2x+1+3(x-3))((2x+1-3(x-3))=0
(5x-8)(-x-8)=0
x=8/5 x=-8

2. 10x^2-11x-6=0
(5x+2)(2x-3)=0
x=-2/5 x=3/2
3. 9(x-2)^2=4(x+1)^2
9(x-2)^2-4(x+1)^2=0
(3(x-2)+2(x+1))(3(x-2)-2(x+1))=0
(5x-4)(x-8)=0
x=4/5 x=8
4. (4x-1)^2+10(1-4x)-24=0
(4x-1)^2-10(4x-1)-24=0
(4x-1-12)(4x-1+2)=0
(4x-13)(4x+1)=0
x=13/4 x=-1/4

Answer 2

You're welcome

Answer 3

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