Question

哪位数学高手帮忙啊，解一道初中数学二次根式题

急急急急急急急！9×根号下32分之一，再÷(负的2分之3×根号下6.75)跪求哪位高手帮忙。

Answer 1

我来帮你
9×√1/32÷（-2/3×√6.75)
=9*1/4√2÷(-2/3×√27/4)
=9/4√2÷(-2/3×3/4√3)
=9/4√2÷1/2√3
=9/2√2÷√3
=3/2√6

Answer 2

我的回答是 结果是—3/8√6
9×√1/32÷（—2/3×√6.75)
=9*1/4√1/2÷(—2/3×√27/4)
=9/8√2÷(—2/3×3/2√3)
=9/8√2÷(—√3)
=—9/8√2÷√3
=—3/8√6

Answer 3

9×√1/32÷（-2/3×√6.75)
=9*1/8√2÷(-3/2×√27/4)
=9/8√2÷(-3/2×3/2√3)
=-9/8√2÷9/4√3
=-1/2√2÷√3
=-1/6√6

Answer 4

负的六分之根号六。。。。 楼上的，是二分之三，不是三分之二 = =。

Answer 5

9×√1/32÷（-2/3×√6.75)
=9*1/4√2÷(-2/3×√27/4)
=9/4√2÷(-2/3×3/4√3)
=9/4√2÷1/2√3
=9/2√2÷√3
=3/2√6

Answer 6

9×√1/32÷（-2/3×√6.75)
=9*1/4√2÷(-2/3×√27/4)
=9/4√2÷(-2/3×3/4√3)
=9/4√2÷1/2√3
=9/2√2÷√3
=3/2√6