
计算:(2^2+1) (2^4+1) (2^8+1) (2^16+1)+……+(2^64+1) 请问这道题答案是多少?
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(2-1)(2+1)(2^2+1) (2^4+1) (2^8+1) (2^16+1)+……+(2^64+1)/3
=(2²-1)(2^2+1) (2^4+1) (2^8+1) (2^16+1)+……+(2^64+1)/3
=(2^4-1) (2^4+1) (2^8+1) (2^16+1)+……+(2^64+1)/3
……
=(2^128-1)/3
=(2²-1)(2^2+1) (2^4+1) (2^8+1) (2^16+1)+……+(2^64+1)/3
=(2^4-1) (2^4+1) (2^8+1) (2^16+1)+……+(2^64+1)/3
……
=(2^128-1)/3
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