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1+2+3+……+n=n(n+1)/2
∴1/(1+2+3+……+n)=2/n(n+1)
1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...+100)
=2/1*2+2/2*3+2/3*4+……+2/100*101
=2(1/1*2+1/2*3+1/3*4+……+1/100*101)
=2(1-1/2+1/3-1/3+1/4-1/4+……-1/100+1/100-1/101)
=2(1-1/101)
=200/101
∴1/(1+2+3+……+n)=2/n(n+1)
1+1/(1+2)+1/(1+2+3)+...+1/(1+2+3+...+100)
=2/1*2+2/2*3+2/3*4+……+2/100*101
=2(1/1*2+1/2*3+1/3*4+……+1/100*101)
=2(1-1/2+1/3-1/3+1/4-1/4+……-1/100+1/100-1/101)
=2(1-1/101)
=200/101
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解:原式=1+1/3+1/6+1/10+...+1/5050
=1+1-2/3+2/3-2/4+2/4-2/5+...+2/100-2/101
=1+2﹙1/2-1/3+1/3-1/4+1/4-1/5+…………+1/100-1/101﹚
=1+2﹙1/2-1/101﹚
=1+1-2/101
=200/101
=1+1-2/3+2/3-2/4+2/4-2/5+...+2/100-2/101
=1+2﹙1/2-1/3+1/3-1/4+1/4-1/5+…………+1/100-1/101﹚
=1+2﹙1/2-1/101﹚
=1+1-2/101
=200/101
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展开全部
解:原式=1+2﹙1/2-1/3+1/3-1/4+1/4-1/5+…………+1/100-1/101﹚
=1+2﹙1/2-1/101﹚
=1+1-2/101
=201/101
=1+2﹙1/2-1/101﹚
=1+1-2/101
=201/101
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