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1-x^2≥0
x^2≤1
-1≤x≤1 (1)
and
x^2-1≥0
x^2 ≥ 1
x≥1 or x≤-1 (2)
(1) and (2)
=> x =1 or -1
f(x) = √(1-x^2) + √(x^2-1)
f(1)= 0+0 =0
f(-1) =0+0 =0
ie
f(x) = √(1-x^2) + √(x^2-1) = 0 ; x= -1 or 1
x^2≤1
-1≤x≤1 (1)
and
x^2-1≥0
x^2 ≥ 1
x≥1 or x≤-1 (2)
(1) and (2)
=> x =1 or -1
f(x) = √(1-x^2) + √(x^2-1)
f(1)= 0+0 =0
f(-1) =0+0 =0
ie
f(x) = √(1-x^2) + √(x^2-1) = 0 ; x= -1 or 1
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