Question

如何JAVA用applet paint根据输入数字画阶梯型图形？

如题， 先弹出一个对话框，要你输入随便数字，然后根据你输入的数字，画相应的几格阶梯，对话框我弄出来的，不懂怎样根据所输入数字画相应的阶梯，我大致草稿如下，请大师帮忙指导，完成余下的， 谢谢
package assignment;
import java.util.Scanner;
import javax.swing.JOptionPane;
import java.applet.*;
import java.awt.*;

public class Q5 extends Applet
{
public static void main(String[] args)
{
Scanner reader = new Scanner(System.in);
String inputno;
int no;

inputno = JOptionPane.showInputDialog("Enter no of steps.");
no = Integer.parseInt(inputno);
}
public void paint(Graphics g)
{
g.drawLine(10, 10, 100, 10);
g.drawLine(100, 10, 100, 100);
}
}

Answer 1

paint函数里加点料就行了。

public void paint(Graphics g){

        int x=100,y=100,num=10;

        for(int i=1;i<num;i++){

            if(i%2==1){

                g.drawLine(x, y, (x=x+20), y);

            }else{

                g.drawLine(x, y, x, (y=y+20));

            }

        }    

}

追问

?/你在么 。。。。还是不可以呢。。。

追答

public class Q5JFrame extends JFrame{
int num;
public Q5JFrame(int i){
num=i;
init();
}
public void init(){
this.setSize(800, 600);
this.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
this.setLocation(1440/2-this.getWidth()/2, 900/2-this.getHeight()/2);
// this.setResizable(false);
this.setVisible(true);
}
@Override
public void paint(Graphics g){
super.paint(g);
draw(g);
}
public void draw(Graphics g){
int x=100,y=100;
for(int i=1;i<num;i++){
if(i%2==1){
g.drawLine(x, y, (x=x+20), y);
}else{
g.drawLine(x, y, x, (y=y+20));
}
}
}
public static void main(String args[]){
Scanner reader = new Scanner(System.in);
String inputno;
int no;
inputno = JOptionPane.showInputDialog("Enter no of steps.");
no = Integer.parseInt(inputno);
Q5JFrame frame = new Q5JFrame(no);
}
}