Question

[(a-b)^2)]^3÷(b-a)÷[(a-b)^2·(b-a)^3]怎么算，要过程

(x-2y)^3·(2y-x)^4÷（2y-x）^2÷(x-2y)^5

Answer 1

[(a-b)^2)]^3÷(b-a)÷[(a-b)^2·(b-a)^3]
=[(b-a)^2)]^3÷(b-a)÷[(a-b)^2·(b-a)^3]
=(b-a)^6÷(b-a)÷[(b-a)^2·(b-a)^3]
=(b-a)^6÷(b-a)÷(b-a)^5
=(b-a)^(6-1-5)
=(b-a)^0
=1

(x-2y)^3·(2y-x)^4÷（2y-x）^2÷(x-2y)^5
=(x-2y)^3·(x-2y)^4÷（x-2y）^2÷(x-2y)^5
=(x-2y)^7÷（x-2y）^2÷(x-2y)^5
=(x-2y)^(7-2-5)
=(x-2y)^0
=1

Answer 2

（a-b）^6÷ -（a-b）÷[(a-b)^2 * -(a-b)^3]
=-(a-b)^5 ÷ -(a-b)^5
=1