Question

18(a+b)^3-12b(b-a)^2因式分解

我都初中念完好几年了，请大侠帮忙

Answer 1

由题意得
=18(a+b)(b+a)²-12b(b－a)²
=18(a+b)(a+b)²-12b(b-a)(b+a)
=3(a+b)[6(a+b)²-4b(b-a)]
=3(a+b)(6a²+12ab+6b²-4b²+4ab)
=6(a+b)(3a²+6ab+3b²-2b²+2ab)
=6(a+b)(3a²+8ab+b²)

Answer 2

18(a＋b)³－12b(b－a)²
=18(a+b)(b+a)²-12b(b－a)²
=18(a+b)(a+b)²-12b(b-a)(b+a)
=3(a+b)[6(a+b)²-4b(b-a)]
=3(a+b)(6a²+12ab+6b²-4b²+4ab)
=6(a+b)(3a²+6ab+3b²-2b²+2ab)
=6(a+b)(3a²+8ab+b²)

Answer 3

18(a＋b)³－12b(b－a)²
=18(a+b)(b+a)²-12b(b－a)²
=18(a+b)(a+b)²-12b(b-a)(b+a)
=3(a+b)[6(a+b)²-4b(b-a)]
=3(a+b)(6a²+12ab+6b²-4b²+4ab)
=6(a+b)(3a²+6ab+3b²-2b²+2ab)
=6(a+b)(3a²+8ab+b²)