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A(2n-1)/B(2n-1)=(7(2n-1)+45)/((2n-1)+3)=(14n+38)/(2n+2)=(7n+19)/(n+1)
[(2n-1)[an+a(2n-1)]/2]/[(2n-1)[bn+b(2n-1)]/2]=(7n+19)/(n+1)
2an/2bn=(7n+19)/(n+1)
an/bn=7+(12/(n+1))
n=1,2,3,5,11时an/bn为整数
A(2n-1)/B(2n-1)=(7(2n-1)+45)/((2n-1)+3)=(14n+38)/(2n+2)=(7n+19)/(n+1)
[(2n-1)[an+a(2n-1)]/2]/[(2n-1)[bn+b(2n-1)]/2]=(7n+19)/(n+1)
2an/2bn=(7n+19)/(n+1)
an/bn=7+(12/(n+1))
n=1,2,3,5,11时an/bn为整数
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