Question

（3x²/4y)²×2y/3x+x²/2y²÷2y²/x 急急急求 下面还一题~

（a+b/a-b）²×2a-2b/3a+3b-a²/a²-b²÷a/b

Answer 1

解1题： ^ 表示乘方
原式=9x^4/(16y²)×2y/(3x)+x²/(2y²)×x/(2y²)
=3x³/(8y)+x³/(4y^4)
=3x³y³/(8y^4)+2x³/(8y^4)
=(3x³y³+2x³)/(8y^4)

解2题：原式=[(a+b)²/(a-b)²]×2(a-b)/[3(a+b)]-a²/[(a+b)(a-b)]×b/a
=2(a+b)/[3(a-b)]-ab/[(a+b)(a-b)]
=2(a+b)²/[3(a+b)(a-b)]-3ab/[3(a+b)(a-b)]
=(2a²+4ab+2b²-3ab)/[3(a+b)(a-b)]
=(2a²+ab+2b²)/[3(a+b)(a-b)]

Answer 2

1.（3x²/4y)²×2y/3x+x²/2y²÷2y²/x
=（3x²/4y)²×2y/3x+x²/2y²×x/2y²
=3x/8y+x³/(4y^4)
=3xy³/(8y^4)+2x³/(8y^4)
=(3xy³+2x³)/(8y^4)
2.（a+b/a-b）²×2a-2b/3a+3b-a²/a²-b²÷a/b
=[(a+b)²/(a-b)²]*2(a-b)/3(a+b)-a²/[(a+b)(a-b)]*(b/a)
=2(a+b)/[3(a-b)]-ab/[(a+b)(a-b)]
=2(a+b)²/[3(a-b)(a+b)]-3ab/[3((a+b)(a-b)]
=(2a²+2b²+ab)/[3(a+b)(a-b)]

Answer 3

x^3(3y^3+2)/8y^4