化简[（X+1/X)^6-（X^6+1/X^6)-2]/[(X+1/X)^3+(X^3+1/X^3)]
2个回答
展开全部
[（x+1/x)^6-(x^6+1/x^6)-2]/[(x+1/x)^3+(x^3+1/x^3)]
=[（x+1/x)^6-(x^6+1/x^6+2)]/[(x+1/x)^3+(x^3+1/x^3)]
=[（x+1/x)^6-(x^3+1/x^3)^2]/[(x+1/x)^3+(x^3+1/x^3)]
=[(x+1/x)^3+(x^3+1/x^3)][(x+1/x)^3-(x^3+1/x^3)]/[(x+1/x)^3+(x^3+1/x^3)]
=(x+1/x)^3-(x^3+1/x^3)
=(x^3+1/x^3+3x+3/x)-(x^3+1/x^3)
=3x+3/x.
=[（x+1/x)^6-(x^6+1/x^6+2)]/[(x+1/x)^3+(x^3+1/x^3)]
=[（x+1/x)^6-(x^3+1/x^3)^2]/[(x+1/x)^3+(x^3+1/x^3)]
=[(x+1/x)^3+(x^3+1/x^3)][(x+1/x)^3-(x^3+1/x^3)]/[(x+1/x)^3+(x^3+1/x^3)]
=(x+1/x)^3-(x^3+1/x^3)
=(x^3+1/x^3+3x+3/x)-(x^3+1/x^3)
=3x+3/x.
本回答由网友推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
