Question

对数不同底数相乘如何运算,(log以4为底3+log以8为底3)*(log3为底2+log9为底2)求教~

Answer 1

=(lg3/lg4+lg3/lg8)(lg2/lg3+lg2/lg9
=(lg3/2lg2+lg3/3lg2)(lg2/lg3+lg2/2lg3)
然后用乘法分配率意义乘开，然后约分，答案就为5/4

Answer 2

=[1/2log(2)3+1/3log(2)3]*[log(3)2+1/2log(3)2]
=5/6log(2)3*3/2log(3)2
=5/4
结果怎么不是4/5？

Answer 3

换底运算

Answer 4

,(log以4为底3+log以8为底3)*(log3为底2+log9为底2)
=(log以4为底3+1/2log以4为底3)*(log3为底2+1/2log3为底2)
=3/2log以4为底3*3/2log3为底2
=9/4log以4为底3*log3为底2

追问

...我也算到这停了后边不会了 答案是4/5 就是解不出来