
先化简,再求值:x^2+2x+1/x+2 ÷x^2-1/x-1 - 1/x+2,其中x=1/2
3个回答
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x^2+2x+1/x+2 ÷x^2-1/x-1 - 1/x+2
=(x+1)²/(x+2)÷(x+1)(x-1)/(x-1)- 1/(x+2)
=(x+1)²/(x+2)×1/(x+1)- 1/(x+2)
=(x+1)/(x+2) -1/(x+2)
=x+1-1/x+2
=x/x+2
把x=1/2代入
原式=x/x+2
=1/2÷(1/2+2)
=1/5
=(x+1)²/(x+2)÷(x+1)(x-1)/(x-1)- 1/(x+2)
=(x+1)²/(x+2)×1/(x+1)- 1/(x+2)
=(x+1)/(x+2) -1/(x+2)
=x+1-1/x+2
=x/x+2
把x=1/2代入
原式=x/x+2
=1/2÷(1/2+2)
=1/5
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