(Sn+1)=(n+2)Sn-(n+1)(Sn-1)
1个回答
展开全部
(Sn+1)=(n+2)Sn-(n+1)(Sn-1)
s3=4s2-3s1
(Sn+1)=(n+2)Sn-(n+1)(Sn-1)
(Sn+1)=(n+1)Sn+Sn-(n+1)(Sn-1)
(Sn+1)-Sn=(n+1)(Sn-(Sn-1))
((Sn+1)-Sn)/(Sn-(Sn-1))=n+1
a(n+1)/an=n+1
an/a(n-1)=n
a(n-1)/a(n-2)=n-1
....
a2/a1=2
an/a1=2*3*...*(n-1)*n
an=a1*n!
s3=4s2-3s1
(Sn+1)=(n+2)Sn-(n+1)(Sn-1)
(Sn+1)=(n+1)Sn+Sn-(n+1)(Sn-1)
(Sn+1)-Sn=(n+1)(Sn-(Sn-1))
((Sn+1)-Sn)/(Sn-(Sn-1))=n+1
a(n+1)/an=n+1
an/a(n-1)=n
a(n-1)/a(n-2)=n-1
....
a2/a1=2
an/a1=2*3*...*(n-1)*n
an=a1*n!
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询