高等数学偏导问题,如图
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是B啊,
p(y)dz/dx=p(y)dz/du*du/dx=p(y)dz/du*(dfai/du*du/dx)
p(x)dz/dy=p(x)dz/du*du/dy=p(x)dz/du*(dfai/du*du/dy)
令du/dx=m,du/dy=n
m=dfai/du*m+p(x),n=dfai/du*n-p(y)
∴m=p(x)/(1-dfai/du) ,n=-p(y)/(1-dfai/du)
∴p(y)dz/du*[p(x)*dfai/du/(1-dfai/du)], p(x)dz/du*[-p(y)*dfai/du/(1-dfai/du)],相加得0
p(y)dz/dx=p(y)dz/du*du/dx=p(y)dz/du*(dfai/du*du/dx)
p(x)dz/dy=p(x)dz/du*du/dy=p(x)dz/du*(dfai/du*du/dy)
令du/dx=m,du/dy=n
m=dfai/du*m+p(x),n=dfai/du*n-p(y)
∴m=p(x)/(1-dfai/du) ,n=-p(y)/(1-dfai/du)
∴p(y)dz/du*[p(x)*dfai/du/(1-dfai/du)], p(x)dz/du*[-p(y)*dfai/du/(1-dfai/du)],相加得0
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