分解因式(过程)
-a+2a^2-a^3(x^2+y^2)^2-4x^2y^2x^3z-4x^2yz+4xy^2z(x+2)(x+3)+x^2-4...
-a+2a^2 -a^3
(x^2 +y^2)^2 -4x^2y^2
x^3z -4x^2yz +4xy^2z
(x+2)(x+3)+x^2 -4 展开
(x^2 +y^2)^2 -4x^2y^2
x^3z -4x^2yz +4xy^2z
(x+2)(x+3)+x^2 -4 展开
1个回答
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(1)-a+2a^2 -a^3
= -(a - 2a^2 + a^3)
= -a(a^2 - 2a + 1)
= -a(a - 1)^2
(2)(x^2 +y^2)^2 -4x^2y^2
= x^4 + 2x^2y^2 + y^4 - 4x^2y^2
= x^4 - 2x^2y^2 + y^4
= (x^2 - y^2)^2
(3) x^3z -4x^2yz +4xy^2z
= xz(x^2 - 4xy + 4y^2)
= xz(x- 2y)^2
(4)(x+2)(x+3)+x^2 -4
= (x + 2)(x + 3) + (x + 2)(x - 2)
= (x + 2)(x + 3 + x - 2)
=(x + 2)(2x + 1)
= -(a - 2a^2 + a^3)
= -a(a^2 - 2a + 1)
= -a(a - 1)^2
(2)(x^2 +y^2)^2 -4x^2y^2
= x^4 + 2x^2y^2 + y^4 - 4x^2y^2
= x^4 - 2x^2y^2 + y^4
= (x^2 - y^2)^2
(3) x^3z -4x^2yz +4xy^2z
= xz(x^2 - 4xy + 4y^2)
= xz(x- 2y)^2
(4)(x+2)(x+3)+x^2 -4
= (x + 2)(x + 3) + (x + 2)(x - 2)
= (x + 2)(x + 3 + x - 2)
=(x + 2)(2x + 1)
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