八年级上册数学题目6.7.题,谢谢
1个回答
展开全部
(1)(x-y)²-x(x-2y)
=x²-2xy+y²-x²+2xy
=y²
(2)(-3x-2y)²
=(3x+2y)²
=9x²+12y+4y²
(3)(x+1)²-2(x-2)
=x²+2x+1-2x+4
=x²+5
(4)(3x+2y)²+(x+2y)(x-2y)
=9x²+12xy+4y²+x²-4y²
=10x²+13xy
=x²-2xy+y²-x²+2xy
=y²
(2)(-3x-2y)²
=(3x+2y)²
=9x²+12y+4y²
(3)(x+1)²-2(x-2)
=x²+2x+1-2x+4
=x²+5
(4)(3x+2y)²+(x+2y)(x-2y)
=9x²+12xy+4y²+x²-4y²
=10x²+13xy
追答
(x+1)(x-1)+x(2-x)+(x+1)²
=x²-1+2x-x²+x²+2x+1
=x²+4x
x=2√3
原式=x²+4x
=(2√3)²+4×2√3
=12+8√3
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询