Question

解{x+y+z=1 2x+3y+2z=2 x+5y+19z=4要过程，答对给满意

Answer 1

x+y+z=1 ①
2x+3y+2z=2 ②
x+5y+19z=4 ③
由②-2×①得 y=0
由③-①得 4y+18z=3 ④
将y=0代入④得 4+18z=3 z=1/6
将y=0 z=1/6 代入①得 x+0+1/6=1 x=5/6
所以x=5/6 y=1 z=1/6

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Answer 2

(2)-(1)*2得 y=0
代入(1),(3)得
x+z=1
x+19z=4
两方程相减,得z=1/6
所以 x=5/6, y=0.z=1/6

Answer 3

x+y+z=1(1)
2x+3y+2z=2(2)
x+5y+19z=4(3)
(1)*2 2x+2y+2z=2(4)
(2)-(4) y=0
x+z=1
x+19z=4
18z=3
z=1/6
x=1-z=1-1/6=5/6
x=5/6,y=0,z=1/6