Question

(2x/x²-4-1/x-2)×x+2/x-1

Answer 1

原式=[2x/(x+2)(x-2)-1/(x-2)]×(x+2)/(x+1)
=(2x-x-2)/(x+2)(x-2)×(x+2)/(x+1)
=(x-2)/(x+2)(x-2)×(x+2)/(x+1)
=1/(x+1)

追问

答案是1/x-1，请再看一下

追答

哦，对不起，我写错了
吧x-1看成x+1了

原式=[2x/(x+2)(x-2)-1/(x-2)]×(x+2)/(x-1)
=(2x-x-2)/(x+2)(x-2)×(x+2)/(x-1)
=(x-2)/(x+2)(x-2)×(x+2)/(x-1)
=1/(x-1)

Answer 2

{[(x+2)+(x-2)]/[(x+2)(x-2)]-1/(x-2)}(x+2)/(x-1)=[1/(x-2)+1/(x+2)-1/(x-2)](x+2)/(x-1)=[1/(x+2)](x+2)/(x-1)=1/(x-1). 分不清楚括号在哪儿，只能猜测了，呵呵。

Answer 3

(2x/x²-4-1/x-2)×x+2/x-1
=[2x/(x+2)(x-2)-1/(x-2)]×(x+2)/(x-1)
=[2x/(x+2)(x-2)-(x+2)/(x+2)(x-2)]×(x+2)/(x-1)
=[(2x-(x-2))/(x+2)(x-2)]×(x+2)/(x-1)
=(x-2)/(x+2)(x-2)×(x+2)/(x-1)
=1/(x+2)×(x+2)/(x-1)
=1/(x-1)

Answer 4

Answer 5

10