Question

一道数学计算题(关于log),要详细步骤

Answer 1

原式=3*3^(log3(6)+10^(lg(3^3))+3^[(-2)*log3(4)]=3*6+27+3^(log3(4^(-2)）=18+27+1/16=45+1/16,记住这个公式a的loga（x）次方=x,此类题目便可以迎刃而解哈~要记住这个公式哈~

Answer 2

3^(1+log3(6))+10^(3lg(3))+(1/9)^(log3(4))
=3*3^log3(6)+10^lg(3^3)+(3^log3(4))^(-2)
=3*6+3^3+4^(-2)
=18+27+1/16
=45+1/16
=721/16
主要用到：a^loga(b)=b
有不懂欢迎追问

Answer 3

Answer 4

原式=3^(1+log3(3×2))+10^lg(3^3)+ 3^(-2log3(2^2))
=3^(1+log3(3)+log3(2))+3^3+3^(-4log3(2))
=3^(2+log3(2))+27+(3^log3(2))^(-4)
=3^2×3^log3(2)+27+2^(-4)
=9×2+27+1/16
=45+1/16
=721/16

Answer 5