Question

C c++幸运数问题

Description:
给定三个整数(0≤A1,A2,A3≤10000)，请找出第一个不大于168的数。如果存在该数,输出"CRASH"并空一格输出该数，否则输出"NO CRASH"。遇到A1=A2=A3=-1则运行结束。

Sample Input:
180 160 170
169 170 200
-1 -1 -1
Sample Output:
CRASH 160
NO CRASH

Answer 1

#include "stdafx.h"
#include "stdio.h"

void main ()
{
int a1 = 0,a2 = 0,a3 = 0;

while( (a1 != -1)||(a2 != -1)||(a3 != -1) )
{
printf("input 3 num\n");
scanf("%d%d%d",&a1,&a2,&a3);
if((a1>=0 && a1<=10000)&&(a2>=0 && a2<=10000)&&(a3>=0 && a3<=10000))
if (a1<168)
printf("CRASH %d\n",a1);
else
if (a2<168)
printf("CRASH %d\n",a2);
else
if (a3<168)
printf("CRASH %d\n",a3);
else printf("NO CRASH\n");

}
}

Answer 2

#include <stdio.h>

int main(void)
{
int a1,a2,a3,c=0;
do
{
scanf("%d%d%d",&a1,&a2,&a3);
if (a1<0||a2<0||a3<0) continue;
if (a1<168) printf("CRASH %d\n",a1);
else if (a2<168) printf("CRASH %d\n",a2);
else if (a3<168) printf("CRASH %d\n",a3);
else puts("NO CRASH");
}while (a1*a2*a3!=-1);

return 0;
}