Question

解方程：（x+1）(x²+x+1)-(x-1)(x²-x+1)=(4x+3)(x-2)

快快快。

Answer 1

(x+1)(x²+x+1)-(x-1)(x²-x+1)=(4x+3)(x-2)
(x+1)(x²-x+1+2x)-(x-1)(x²+x+1-2x)=(4x+3)(x-2)
(x+1)(x²-x+1)+2x(x+1)-(x-1)(x²+x+1)+2x(x-1)=(4x+3)(x-2)
x^3+1+2x(x+1)-(x^3-1)+2x(x-1)=(4x+3)(x-2)
x^3+1+2x(x+1)-x^3+1+2x(x-1)=(4x+3)(x-2)
2x(x+1)+2x(x-1)+2=(4x+3)(x-2)
2x(x+1+x-1)+2=(4x+3)(x-2)
4x^2+2=4x^2-5x-6
2=-5x-6
5x=-8
x=-8/5

Answer 2

（x+1）(x²+x+1)-(x-1)(x²-x+1)=(4x+3)(x-2)

x^3+x^2+x+x^2+x+1-x^3+x^2-x+x^2-x+1=4x^2-5x-6
2x^2-5x-8=0
x=(5±√89)/4

Answer 3

x^3+x^2+x+x^2+x+1-x^3+x^2-x+x^2-x+1=4x^2-8x+3x-6
4x^2+2=4x^2-5x-6
5x=-8
x=-8/5

Answer 4

额，我才6年级