Question

函数f（x）＝cos2x－2√3sinxcosx的最小正周期是

Answer 1

f(x)＝cos2x－2√3sinxcosx
=cos2x-√3sin2x
=2(cos2x*1/2-sin2x*√3/2)
=2(cos2x*cosπ/3-sin2xsinπ/3)
=2cos(2x+π/3)
最小正周期=2π/2=π
如果你认可我的回答，请点击“采纳为满意答案”,祝学习进步！
手机提问的朋友在客户端右上角评价点【满意】即可

Answer 2

f（x）＝cos2x－√3sin2x=2*(1/2 *cos2x - √3/2 * sin 2x)=2*sin(π/6-2x)=-2*sin(2x-π/6) 所以最小正周期是 π！ 望楼主采纳 金榜题名！