Question

利用矩阵的初等变换，求方阵的逆阵（3 -2 0 -1 0 2 2 1 1 -2 -3 -2 0 1 2 1）

Answer 1

(A,E) =
3 -2 0 -1 1 0 0 0
0 2 2 1 0 1 0 0
1 -2 -3 -2 0 0 1 0
0 1 2 1 0 0 0 1

r1-3r3
0 4 9 5 1 0 -3 0
0 2 2 1 0 1 0 0
1 -2 -3 -2 0 0 1 0
0 1 2 1 0 0 0 1

r1-4r4,r2-2r4,r3+2r4
0 0 1 1 1 0 -3 -4
0 0 -2 -1 0 1 0 -2
1 0 1 0 0 0 1 2
0 1 2 1 0 0 0 1

r2+2r1,r3-r1,r4-2r1
0 0 1 1 1 0 -3 -4
0 0 0 1 2 1 -6 -10
1 0 0 -1 -1 0 4 6
0 1 0 -1 -2 0 6 9

r1-r2,r3+r2,r4+r2
0 0 1 0 -1 -1 3 6
0 0 0 1 2 1 -6 -10
1 0 0 0 1 1 -2 -4
0 1 0 0 0 1 0 -1

交换行
1 0 0 0 1 1 -2 -4
0 1 0 0 0 1 0 -1
0 0 1 0 -1 -1 3 6
0 0 0 1 2 1 -6 -10

得 A^-1 =
1 1 -2 -4
0 1 0 -1
-1 -1 3 6 2 1 -6 -10

Answer 2

1 1 -2 -4
0 1 0 -1
-1 -1 3 6
2 1 -6 -10

追问

过程能写出来吗