Question

物理题目 求过程

Answer 1

(ρ砖Vg+ρV混g)/s=ρ砖hg+ρh混g=900pa
900n =100×105×0.1
n=1/9 ×104
h=1/9 ×104×0.054=60米

Answer 2

解：设极限高度是H则：
p砖g(5/5.4)H+ p混g(0.4/5.4)H=100x10^5
(1.6x10^3x10x0.926+2.5x10^3x10x0.074)H=100x10^5
H=600m
所以墙的最大高度为：h=0.1H=60m
望采纳！