Question

已知|a-2|+(b+1/4)^2=0，求(a^b-2ab)-2(3ab^2+4ab)的值

Answer 1

|a-2|+(b+1/4)^2=0
∵|a-2|≥0，(b+1/4)^2≥0
∴a-2=0，b+1/4=0
a=2，b=-1/4
(a^b-2ab)-2(3ab^2+4ab)
=a^b-6ab^2-10ab
=2^(1/4)-6*2*(1/4)^2-10*2*1/4
=2^(1/4)-3/4-5
=2^(1/4)-23/4

追问

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追答

题目是不是这样：
已知|a-2|+[(b+1)/4]^2=0，求(a^b-2ab)-2(3ab^2+4ab)的值
|a-2|+(b+1/4)^2=0
因为|a-2|≥0，[(b+1)/4]^2≥0
所以a-2=0，(b+1)/4=0
a=2，b=3
(a^b-2ab)-2(3ab^2+4ab)
=a^b-6ab^2-10ab
=2^3-6*2*3^2-10*2*3
=8-108-60
=-160