Question

关于x,y的多项式6mx^2+4nxy+2x+2xy-x^2+y+4不含二次项，求6m-2n+2的值

Answer 1

6mx^2+4nxy+2x+2xy-x^2+y+4=(6m-1)x^4+(4n+2)xy+2x+y+4
二次项为(6m-1)x^4，(4n+2)xy
不含二次项，则：6m-1=0，4n+2=0
得：6m=1，2n=-1
所以：6m-2n+2=1+1+2=4

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Answer 2

6mx^2+4nxy+2x+2xy-x^2+y+4
=（6m-1)x^2+(4n+2)xy+2x+y+4
关于x,y的多项式6mx^2+4nxy+2x+2xy-x^2+y+4不含二次项
6m-1=0, 4n+2=0
m=1/6,n=-1/2
6m-2n+2=6x1/6-2x(-1/2)+2=4

Answer 3

6mx²+4nxy+2x+2xy-x²+y+4
=(6m-1)x²+(4n+2)xy+2x+y+4
∵多项式不含二次项
∴6m-1=0
4n+2=0
∴m=1/6
n=-1/2
∴6m-2n+2
=6*1/6-2*(-1/2)+2
=1+1+2
=4

Answer 4

6m+4n+2-1=0
他的对了，我就不写了

Answer 5

6mx^2+4nxy+2x+2xy-x^2+y+4
=(6m-1)x^2+(4n+2)xy+2x+y+4
不含二次项
所以二次项系数=0
即6m-1=4n+2=0
6m=1,4n=-2,2n=-1
所以6m-2n+2=1-(-1)+2=1+1+2=4