Question

c语言编程题，求大神帮忙

从键盘输入十个整数对一个一维数组赋值，并将其中的奇数存放到另一个数组中后再输出，并输出奇数的个数。
如：从键盘输入: 1314 17 34 45 55 56 76 77 99
则输出: 13 17 45 55 77 99
count = 6

Answer 1

1.
int isPrimer(int x){
int i;
for(i=2; i < sqrt(x)+1 ; ++i){
if( x%i == 0) return 0;
}
return 1;
}
2.
#include<stdio.h>
int isSXH(int x){
int i,k=x,sum=0;
while(x>0){
i = x%10;
sum += i*i*i;
x=x/10;
}
if(sum == k) return 1;
return 0;
}

void main(){
for(int i =100 ; i<1000;++i){
if(isSXH(i)) printf("%d ",i);
}
}
3.
#include<stdio.h>
void main()
{
int a,b;
scanf("%d %d",&a,&b);
while(a!=b)
{
if(a>b)
a-=b;
else
b-=a;
}
printf("%d",a);
}
4.

#include <stdio.h>
#define N 20
main(){
int f(int n);
int i;
for(i=1;i<=N;i++){
printf("%-6d",f(i));
if(i%5==0)
printf("\n");
}
printf("\n");
}

int f(int n){
if(n==1 || n==2)
return 1;
else
return (f(n-2)+f(n-1));
}
6.
#include <stdio.h>
int gbs;
void minGBS(int m,int n){
int temp,r,p;
if (n<m){
temp=n;
n=m;
m=temp;
}
p=n*m;
while (m!=0){
r=n%m;
n=m;
m=r;
}
gbs = p/n;
}

int main (){
int m,n;
scanf("%d%d",&m,&n);
minGBS(m,n);
printf("%d\n",gbs);
}
8.
#include <stdio.h>
#define N 20
main(){
int f(int n);
int i;
for(i=1;i<=N;i++){
printf("%-6d",f(i));
if(i%5==0)
printf("\n");
}
printf("\n");
}

int f(int n){
if(n==1 || n==2)
return 1;
else
return (f(n-2)+f(n-1));
}
打字不易，如满意，望采纳。

Answer 2

1.
int isPrimer(int x){
int i;
for(i=2; i < sqrt(x)+1 ; ++i){
if( x%i == 0) return 0;
}
return 1;
}
2.
#include<stdio.h>
int isSXH(int x){
int i,k=x,sum=0;
while(x>0){
i = x%10;
sum += i*i*i;
x=x/10;
}
if(sum == k) return 1;
return 0;
}

void main(){
for(int i =100 ; i<1000;++i){
if(isSXH(i)) printf("%d ",i);
}
}
3.
#include<stdio.h>
void main()
{
int a,b;
scanf("%d %d",&a,&b);
while(a!=b)
{
if(a>b)
a-=b;
else
b-=a;
}
printf("%d",a);
}
4.

#include <stdio.h>
#define N 20
main(){
int f(int n);
int i;
for(i=1;i<=N;i++){
printf("%-6d",f(i));
if(i%5==0)
printf("\n");
}
printf("\n");
}

int f(int n){
if(n==1 || n==2)
return 1;
else
return (f(n-2)+f(n-1));
}
6.
#include <stdio.h>
int gbs;
void minGBS(int m,int n){
int temp,r,p;
if (n<m){
temp=n;
n=m;
m=temp;
}
p=n*m;
while (m!=0){
r=n%m;
n=m;
m=r;
}
gbs = p/n;
}

int main (){
int m,n;
scanf("%d%d",&m,&n);
minGBS(m,n);
printf("%d\n",gbs);
}
8.
#include <stdio.h>
#define N 20
main(){
int f(int n);
int i;
for(i=1;i<=N;i++){
printf("%-6d",f(i));
if(i%5==0)
printf("\n");
}
printf("\n");
}

int f(int n){
if(n==1 || n==2)
return 1;
else
return (f(n-2)+f(n-1));
}
请采纳答案，支持我一下。