Question

c语言:输入一行字符,分别统计出其中英文字母,空格,数字和其它字符的个数

Answer 1

#include<stdio.h>
#define N 100
int main()
{
char a[N];
int i,m=0,n=0,b=0,c=0;
printf("Input a string:");
gets(a);
for(i=0;a[i]!='\0';i++)
{
if(a[i]>='a'&&a[i]<='z'||a[i]>='A'&&a[i]<='Z')
m++;
else if(a[i]>='0'&&a[i]<='9')
n++;
else if(a[i]==' ')
b++;
else
c++;
}
printf("英文字母:%d\n",m);
printf("数字字符：%d\n",n);
printf("空格：%d\n",b);
printf("其他字符：%d\n",c);
return 0;
}

Answer 2

即学了编程又学了英语（没学好……），岂不美哉？
（printf()函数能用那种方式是因版本的关系）

本程序的优点：不受到字符串长度的限制，运行效率高

#include <stdio.h>

int main (void)

{

//Program fuction introduce

printf ("Character statistics.\n");

//Data

char ch;

int letnum = 0;                    //The number of leters

int spanum = 0;                  //The number of space

int dignum = 0;                  //The number of digits

int resnum = 0;                  //The number of other characters

//Data input

printf ("\nPlease input a charactor string.\n");

scanf ("%c", &ch);

//Data processing

while (ch != 10)

{

if  (64 < ch && ch <91 || 96 < ch && ch < 113)

++letnum;

else if (ch == 32)

++spanum;

else if (47 < ch && ch < 58)

++dignum;

else

++resnum;

scanf ("%c", &ch);

}

++resnum;                    //Attention! Because of the newline (ASCII: 10)!

//Data output

printf ("\nThe results of data processing are as fellows.\n");

printf ("The number of letters:%8d\n"

"The number of space: %8d\n"

"The number of digits: %8d\n"

"The number of others:%8d\n",

letnum, spanum, dignum, resnum);    

//The end

printf ("\nThank you for your using!");

return 0;

}

Answer 3

#include<stdio.h>
#define N 100
int main()
{
char a[N];
int i,m=0,n=0,b=0,c=0;
char *p;
printf("Input a string:");
gets(a);
p=a;
for(i=0;p[0]!='\0';i++,p++)
{
if(p[0]>='a'&&p[0]<='z'||p[0]>='A'&&p[0]<='Z')
m++;
else if(p[0]>='0'&&p[0]<='9')
n++;
else if(p[0]==' ')
b++;
else
c++;
}
printf("英文字母:%d\n",m);
printf("数字字符：%d\n",n);
printf("空格：%d\n",b);
printf("其他字符：%d\n",c);
return 0;
}

Answer 4

C语言经典例子之统计英文、字母、空格及数字个数

Answer 5