
初二数学上册
3个回答
展开全部
1. 16m^2-9n^2=(4m)^2-(3n)^2=(4m+3n)(4m-3n)
2. x(x-y-z)+y(y-x+z)+z(z-x+y)
=x^2-xy-xz+y^2-xy+yz+z^2-xz+yz
=x^2-2xy+y^2-2z(x-y)+z^2
=(x-y)^2-2z(x-y)+z^2
=(x-y-z)^2
3. x^2+ax-6=(x+b)(x-2)=(x+3)(x-2)
a=1,b=3
(a+b)^(b-a)=(1+3)^(3-1)=4^2=16
4. a^2b^2-8ab+4a^2+b^2+4=0
=(ab-2)^2+(2a-b)^2=0
则ab=2, 2a-b=0
则a=1或-1
b=2或-2
a=1,b=2,则 3a+(b/2)^2010=4
a=-1,b=-2,则 3a+(b/2)^2010=-4
2. x(x-y-z)+y(y-x+z)+z(z-x+y)
=x^2-xy-xz+y^2-xy+yz+z^2-xz+yz
=x^2-2xy+y^2-2z(x-y)+z^2
=(x-y)^2-2z(x-y)+z^2
=(x-y-z)^2
3. x^2+ax-6=(x+b)(x-2)=(x+3)(x-2)
a=1,b=3
(a+b)^(b-a)=(1+3)^(3-1)=4^2=16
4. a^2b^2-8ab+4a^2+b^2+4=0
=(ab-2)^2+(2a-b)^2=0
则ab=2, 2a-b=0
则a=1或-1
b=2或-2
a=1,b=2,则 3a+(b/2)^2010=4
a=-1,b=-2,则 3a+(b/2)^2010=-4
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