1已知 f(x)=(3x+1)/(4x+2) 求f(x)值域
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f(x) = (3x+1)/(4x+2) = (3x+3/2 - 1/2)/(4x+2)
= (3x+3/2)/(4x+2) - (1/2)/(4x+2) = 3/4 - 1/(8x+4)
lim<x→∞>[3/4 - 1/(8x+4)] = 3/4
lim<x→(-1/2)->[3/4 - 1/(8x+4)] = +∞
lim<x→(-1/2)+>[3/4 - 1/(8x+4)] = -∞
f(x)∈ (-∞, 3/4)∪(3/4, +∞)
= (3x+3/2)/(4x+2) - (1/2)/(4x+2) = 3/4 - 1/(8x+4)
lim<x→∞>[3/4 - 1/(8x+4)] = 3/4
lim<x→(-1/2)->[3/4 - 1/(8x+4)] = +∞
lim<x→(-1/2)+>[3/4 - 1/(8x+4)] = -∞
f(x)∈ (-∞, 3/4)∪(3/4, +∞)
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