Question

因式分解:x^3-28x+48

答案:(x-4)(x-2)(x+6)
求过程

Answer 1

拆项
原式=x³-4x-24x+48
=x(x²-4)-24(x-2)
=x(x+2)(x-2)-24(x-2)
=(x-2)[x(x+2)-24]
=(x-2)(x²+2x-24)
=(x-2)(x-4)(x+6)

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Answer 2

x^3-28x+48
=x³-2x²+2x²-4x-24x+48
=x²(x-2)+2x(x-2)-24(x-2)
=(x-2)(x²+2x-24)
=(x-2)(x+6)(x-4)