
化简[(x²-1)/(x²-2x+1)+(1-x)/(x+1)]÷[x/(x-1)]
1个回答
展开全部
原式=[(x+1)(x-1)/(x-1)²-(x-1)/(x+1)]*(x-1)/x
=[(x+1)/(x-1)-(x-1)/(x+1)]*(x-1)/x
=(x²+2x+1-x²+2x-1)/(x+1)(x-1)*(x-1)/x
=2x/(x+1)(x-1)*(x-1)/x
=2/(x+1)
=[(x+1)/(x-1)-(x-1)/(x+1)]*(x-1)/x
=(x²+2x+1-x²+2x-1)/(x+1)(x-1)*(x-1)/x
=2x/(x+1)(x-1)*(x-1)/x
=2/(x+1)
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询