Question

把3x^2+12xy+11y^2因式分解

Answer 1

解：令3x^2+12xy+11y^2=0，把y看成常数，则解关于X的一元二次方程即可，答案（X+2Y-√3*Y/3)(X+2Y+√3*Y/3)

Answer 2

3x^2+12xy+11y^2
=3x^2+12xy+12y^2-y^2
=3(x+2y)^2-y^2
=[a(x+2y)+y][a(x+2y)-y]
a=根号3

Answer 3

加点分我给你做。。