Question

计算:a-1/(a-2)×（a的2次方-4）/(a的2次方-2a+1)÷1/a的2次方-1

要过程。

Answer 1

啥意思？是分数模式相乘除还是怎么？

追问

分式的运算。

追答

(a-1)/(a-2) * (a²-4)/(a²-2a+1)÷(1/(a²-1))
=(a-1)/(a-2) * (a-2)(a+2)/(a-1)²÷(1/(a-1)(a+1))
=(a+2)/(a-1)÷(1/(a-1)(a+1))
=(a+2)(a-1)(a+1)/(a-1)
=(a+2)(a+1)
=a²+3a+2