在三角形ABC中,已知2B=A+C,b^2=ac,则B-A=？ A.0 B.Π/6 C.Π/4
在三角形ABC中,已知2B=A+C,b^2=ac,则B-A=？A.0B.Π/6C.Π/4D.Π/3...
在三角形ABC中,已知2B=A+C,b^2=ac,则B-A=？
A.0 B.Π/6 C.Π/4 D.Π/3 展开
A.0 B.Π/6 C.Π/4 D.Π/3 展开
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A + B + C = 180, 2B = A + C => B = 60
b^2 = a^2 + c^2 - 2ac * cosB = a^2 + c^2 - ac = ac => (a - c)^2 = 0 => a = c => A = C = 60
B - A = 0
b^2 = a^2 + c^2 - 2ac * cosB = a^2 + c^2 - ac = ac => (a - c)^2 = 0 => a = c => A = C = 60
B - A = 0
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