代数式1/x-1+1/x+1+2x³/x²+1+4x³/x^4+1化简结果为
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1/x-1+1/x+1+2x/x²+1+4x³/x^4+1
=(x+1+x-1)/(x-1)(x+1)+2x/(x²+1)+4x³/(x^4+1)
=2x/(x²-1)+2x/(x²+1)+4x³/(x^4+1)
=[2x(x²+1)+2x(x²-1)]/(x²-1)(x²+1)+4x³/(x^4+1)
=4x³/(x^4-1)+4x³/(x^4+1)
=[4x³(x^4+1)+4x³(x^4-1)]/(x^4-1)(x^4+1)
=8x^7/(x^8-1)
题目打错了,2x³/x²+1这项应该是2x/x²+1
=(x+1+x-1)/(x-1)(x+1)+2x/(x²+1)+4x³/(x^4+1)
=2x/(x²-1)+2x/(x²+1)+4x³/(x^4+1)
=[2x(x²+1)+2x(x²-1)]/(x²-1)(x²+1)+4x³/(x^4+1)
=4x³/(x^4-1)+4x³/(x^4+1)
=[4x³(x^4+1)+4x³(x^4-1)]/(x^4-1)(x^4+1)
=8x^7/(x^8-1)
题目打错了,2x³/x²+1这项应该是2x/x²+1
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