Question

c语言程序设计 输入一个三位数,输出为各个位数上的数的立方和,求答

急急急急

Answer 1

*b#include<stdio.h>
void main(){
int n,a,b,c,sum;

printf("输入一个三位数\n");

scanf("%d",&n);

a=n/100;

b=(n%100)/10;

c=(n%10);

sum=a*a*a+b*b*b+c*c*c;

printf("各个位数上的数的立方和为%d\n",sum);

}

Answer 2

#include <stdio.h>
int calc(int num);
int main(void){
int num=0;
printf("请输入数据，以Ctrl+C结束\n");
while(scanf("%d", &num))
{
printf("%d\n", calc(num));
}

return 0;}
int calc(int num){
int sum = 0;
if (num<100 || num >999)
{
return 0;
}
else
{
while(num)
{
int tmp = num%10;
sum += tmp*tmp*tmp;
num = num/10;
}
}

return sum;}

Answer 3

#include<stdio.h>
main(){
int x,a,b,c;
scanf("%d",&x);
a=x/1000;
b=x/100&10;
c=x%10;
printf("%d",a*a*a+b*b*b+c*c*c);
}

Answer 4

void main()
{
int x,a,b,c;
scanf("%d",&x);
a=x/100;//得到百位
b=(x/10)%10;//得到十位
c=x%10;//得到个位
cout << a << b << c << endl;
printf("%d",a*a*a+b*b*b+c*c*c);
}

Answer 5

int temp, sum, ge, shi, bai;
scanf("%d", &temp);
if(temp>999 || temp<100)
return;

ge = temp%10;
shi = temp/10%10;
bai = temp/100;
sum = ge*ge*ge + shi*shi*shi + bai*bai*bai;
printf("sum = %d", sum);
这个不难的