Question

初中二年级下数学题

｛x²－(y-z)²分之x²-y²｝÷｛（x-y)²-z²分之x²+2xy+y²｝×｛x²-xy分之x²+xy-xz｝

Answer 1

楼主题弄错了吧？以后打分数就打 / 大多数人都能看懂，还有的重视运算的法则。若是觉得打起来容易让人难理解，就照下来再传上来。只要像素还可以其实200万都够了。

若是{(x²-y²)]/[x²-(y-z)²]}÷{(x²+2xy+y²)/[(x-y)²-z²]}×[(x²+xy-xz)/(x²-xy)]

={(x²-y²)]/[x²-(y-z)²]}•{[(x-y)²-z²]/(x²+2xy+y²)}•[(x²+xy-xz)/(x²-xy)]

={(x²-y²)][(x-y)²-z²](x²+xy-xz)}÷{[x²-(y-z)²](x²+2xy+y²)(x²-xy)]}

=[(x-y)(x+y)(x-y-z)(x-y+z)(x+y-z)x]÷[(x-y+z)(x+y-z)(x+y)²(x-y)x]

=(x-y-z)/(x+y)

若是[x²－(x²-y²)/(y-z)²]÷[(x-y)²-(x²+2xy+y²)/z²]×[x²-(x²+xy-xz)/(xy)]只能消掉其中的一部分，没多大意义

若是[x²－x²/(y-z)²-y²]÷[(x-y)²-x²/z²+2xy+y²]×[x²-x²/(xy)+xy-xZ]还是只能消掉其中的一部分，没多大意义

追问

确定？

追答

确定啊，你传张照片上来吧，那样不会把题意弄错

 

Answer 2

解 （x+y)(x-y) ( x-y+z)(x-y-z) x(x+y-z)
= ──────────×─────────× ───────
(x+y-z)(x+z-y) ( x+y)² x(x-y)
x-y-z
=───────
x+y

Answer 3

Answer 4

解 （x+y)(x-y) ( x-y+z)(x-y-z) x(x+y-z)
= ──────────×─────────× ───────
(x+y-z)(x+z-y) ( x+y)² x(x-y)
x-y-z
=───────
x+y