Question

化简√3sin(π/6-α)-cos(π/-α) 请写下过程，谢谢！！

√3sin(π/6-α)-cos(π/6-α)
打漏了~~~

Answer 1

√3sin(π/6-α)-cos(π/6-α)
=2[cosπ/6 sin(π/6-α)-sinπ/6 cos(π/6-α)]
=2sin(π/6-α-π/6]=-2sinα

Answer 2

？？？√3sin(π/6-α)-cos(π/6-α)
=√3sinπ/6cosα-cosπ/6sinα-cosπ/6cosα-sinπ/6sinα
=3/2cosα-√3/2sinα-√3/2cosα-1/2sina
=(√3-1)/2sina